Function replaceinds_in_place 

pub fn replaceinds_in_place<I: IndexLike>(
    indices: &mut [I],
    replacements: &[(I, I)],
) -> Result<(), ReplaceIndsError>

Replace indices in-place based on ID matching.

This is an in-place variant of replaceinds that modifies the input slice directly. Useful for performance-critical code where you want to avoid allocations.

Arguments

• indices - Mutable slice of indices to modify
• replacements - Pairs of (old_index, new_index) where indices matching old_index.id are replaced with new_index

Returns

Ok(()) on success, or an error if any replacement has a dimension mismatch.

Errors

Returns ReplaceIndsError::SpaceMismatch if any replacement index has a different dimension than the original.

Example

use tensor4all_core::index::{DefaultIndex as Index, DynId};
use tensor4all_core::index_ops::replaceinds_in_place;

let i = Index::new_dyn(2);
let j = Index::new_dyn(3);
let k = Index::new_dyn(4);
let new_j = Index::new_dyn(3);

let mut indices = vec![i.clone(), j.clone(), k.clone()];
let replacements = vec![(j.clone(), new_j.clone())];

replaceinds_in_place(&mut indices, &replacements).unwrap();
assert_eq!(indices[1].id, new_j.id);